4x^(5/2)-16=1

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Solution for 4x^(5/2)-16=1 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

4*x^(5/2)-16 = 1 // - 1

4*x^(5/2)-16-1 = 0

4*x^(5/2) = 17 // : 4

x^(5/2) = 17/4

x^(5/2) = 17/4 // ^ 2

x^5 = 289/16 // ^ 1/5

x = (289/16)^(1/5)

x = (289/16)^(1/5)

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